2024年黄花中学初中毕业模拟考试试卷（二）答案

2010年黄花中学初中毕业模拟考试试卷（二）

参考答案

一 . 单项选择题（本题共8个小题，每小题3分，满分24分） 题号 答案 1 B 2 D 3 B 4 B 5 D 6 B 7 C 8 A

二、填空题（本题共8个小题，每小题3分，满分24分）

9、?4 10、x≥1 11、(m?n)(m?x)； 12、１；

４13、20o； 14、30°； 15、

3； 16、1。 5三、解答题（本题共6个小题，每小题6分，满分36分） 17、解：原式?2?3?1?3?1 ······················································································ （5分） ?3．?????????（6分）

x2?4118. 解：原式= ··························································································· 1分 ?2x?2x?2x=

(x?2)(x?2)1 ····································································································· 3分 ?x?2x(x?2)1 ·········································································································································· 4分 x11当x?时，原式=?4． ·································································································· 6分

144m19. 解：（1）由图象可知，函数y?（x?0）的图象经过点A(1，6)，

x可得m?6．????? 2分

=

设直线AB的解析式为y?kx?b．

∵A(1，6)，B(61)，两点在函数y?kx?b的图象上，

y 6 A ∴??k?b?6，?k?1， 解得? ??????4分

?6k?b?1.?b?7.1 O 1 B 6 x ∴直线AB的解析式为y??x?7．

第19题

（2）图中阴影部分（不包括边界）所含格点的个数是 3 ．??????6分 20. 1

21、（1）解：在△AOC中，AC=2，

初中毕业学业考试数学模拟试卷（七）答案 第1页 （共5页）

∵ AO＝OC＝2，

∴ △AOC是等边三角形．??????2分 ∴ ∠AOC＝60°，

∴∠AEC＝30°??????3分 （2）证明：∵OC⊥l，BD⊥l． ∴ OC∥BD．

∴ ∠ABD＝∠AOC＝60°． ∵ AB为⊙O的直径，

∴ △AEB为直角三角形，∠EAB＝30°． ∴∠EAB＝∠AEC．

∴ 四边形OBEC 为平行四边形． ??????5分 又∵ OB＝OC＝2．

∴ 四边形OBEC是菱形．??????6分

22、（1）360°?45%?162°； ····························································································· 2分 （2）40?30%?12；图略． ······························································································· 4分

第21题

l A

O B

C D E （3）40?12?18?6?4，?100%?10%． ··································································· 6分 四、解答题（本题共2个小题，每小题8分，满分16分） 23、解：（1）?OB?4，OE?2，?BE?2?4?6． ?CE⊥x轴于点E．

440?tan?ABO?CE1······································································· （1分） ?，?CE?3． ·

BE23?． ·························································································· （2分） ?点C的坐标为C??2，设反比例函数的解析式为y?将点C的坐标代入，得3?m(m?0)． xm， ?2··················································································································· （3分） ?m??6． ·

6········································································ （4分） ?该反比例函数的解析式为y??． ·x（2）?OB?4，?B(4，····················································································· （5分） 0)． ·

?tan?ABO?OA1?， OB2······························································································· （6分） 2)． ·?OA?2，?A(0，初中毕业学业考试数学模拟试卷（七）答案 第2页 （共5页）

设直线AB的解析式为y?kx?b(k?0)．

将点A、B的坐标分别代入，得??b?2，

?4k?b?0.1??k??，解得?················································································································ （7分） 2

??b?2.1?直线AB的解析式为y??x?2． ????（8分）

224、解：（1）该市政府2008年投入改善医疗服务的资金是：

······························································································· 1分 6000?1250?4750（万元）

（2）设市政府2008年投入“需方”x万元，投入“供方”y万元， 由题意得??x?y?4750，

?(1?30%)x?(1?20%)y?6000.?x?3000，解得? ····················································································································· 3分

y?1750.?， ?2009年投入“需方”资金为(1?30%)x?1.3?3000?3900（万元）2009年投入“供方”资金为(1?20%)y?1.2?1750?2100（万元）．

答：该市政府2009年投入“需方”3900万元，投入“供方”2100万元． ······················· 4分 （3）设年增长率为x，由题意得

6000(1?x)2?7260， ·········································································································· 6分

解得x1?0.1，x2??1.1（不合实际，舍去）

答：从2009~2011年的年增长率是10%． ············································································ 8分 五、解答题（本题共2个小题，每小题10分，满分20分） 25．（1）解：图①表示批发量不少于20kg且不多于60kg的该种水果，

可按5元/kg批发；

金额w（元） 图②表示批发量高于60kg的该种水果，

可按4元/kg批发．???????2分

（2）解：由题意得：w???5n(20≤n≤60)

4n(n?60)?图象如图所示．????5分

由图可知，资金金额满足240?w≤300时， 以同样的资金可批发到较多数量的该种水果． ·············· 6分 （3）解法一：

设当日零售价为x元，由图可得日最高销量n?320?40x

300 240 200 100 O 20 60 批发量n（kg）

25题初中毕业学业考试数学模拟试卷（七）答案 第3页 （共第5页）

当n＞60时，x＜6.5． 由题意，销售利润为

········································· 8分 y?(x?4)(320?40x)?40(x?4)(8?x)?40[?(x?6)2?4] ·从而x＝6时，y最大值?160．此时n＝80．

即经销商应批发80kg该种水果，日零售价定为6元/kg，

当日可得最大利润160元． ································································································· 10分 解法二：

设日最高销量为xkg（x＞60）

则由图（2）日零售价p满足：x?320?40p．于是p?销售利润y?x?320?x， 401?320?x?1····························· 8分 ?4??x(160?x)??(x?80)2?160 ·

404040??从而x＝80时，y最大值?160．此时p＝6．即经销商应批发80kg该种水果，日零售价定为6元/kg，当日可得最大利润160元． ····················································································· 10分

26、（1）EO?EC，理由如下：

由折叠知：EO?EF 在Rt△EFC中，EF为斜边 ?EF?EC 故EO?EC ··························································································································· 2分 （2）m为定值．

?S四边形CFGH?CF2?EF2?EC2?EO2?EC2?(EO?EC)(EO?EC)?CO?(EO?EC)S四边形CMNO?CM·CO?CE?EO·CO?(EO?EC·)CO

?m?S四边形CFGHS四边形CMNO?1 ············································································································· 3分

（3）?CO?1，CE?12，QF? 33121?EF?EO?1???QF ?cos?FEC? ??FEC?60°

332180°-60???FEA??60°=?OEA，?EAO?30°

22······················································································ 4分 ?△EFQ为等边三角形，EQ? ·3作QI?EO于I． EI?3311EQ? EQ? IQ?2323?IO??31?211，? ········································································ 5分 ?? ?Q的坐标为???333?33?初中毕业学业考试数学模拟试卷（七）答案 第4页 （共5页）

，，Q??抛物线y?mx?bx?c过点C(01)2?31?，m?1 ??3，?3??1?3?3????b·?1 b??3 ???3?3?3············································································· 6分 ?所求抛物线解析式为y?x2?3x?1 ·（4）由（3）：AO?3EO?2223 3y H C E I Q G F B 当x?212?2?3??3?3?1??AB 3时，y??333?3?M 1??2······························································ 7分 ?P?3，? ·3??312?BP?1??

x 33N O A 方法1：若△PBK与△AEF相似， 而△AEF≌△AEO．则分情况如下

2?43??823BK?，1或? ······························· 8分 3，1①?3时 BK??K为?????229??9??933322BK?4?········································· 9分 31，3?K为?②?3时 BK??或（0，1） ·2233??333故直线KP与y轴交点T的坐标为?0，················ 10分 ??或?0，?或?0，??或（0，1） ·方法2：△BPK与△AEF相似时，由（3）得则?BPK?30°或60°， 过P点作PR垂直Y轴于R则?RTP?60°或30°

??5?3???7?3???1?3?①当?RTP?30°时，RT?23?3?2 3②当?RTP?60° RT?2325??7???3??T1?0，?，T2?0，?? 333??3??1??1) ???????10分 T3?0，??，T4(0，3??

初中毕业学业考试数学模拟试卷（七）答案 第5页 （共5页）

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